So when I do a code of blocks inside a try{}
, and I try to return
a value, it tells me
no return values
import org.w3c.dom.ranges.RangeException;
public class Pg257E5
{
public static void main(String[]args)
{
try
{
System.out.println(add(args));
}
catch(RangeException e)
{
e.printStackTrace();
}
finally
{
System.out.println("Thanks for using the program kiddo!");
}
}
public static double add(String[] values)
// shows a commpile error here that I don't have a return value
{
try
{
int length = values.length;
double arrayValues[] = new double[length];
double sum = 0;
for(int i = 0; i<length; i++)
{
arrayValues[i] = Double.parseDouble(values[i]);
sum += arrayValues[i];
}
return sum; // I do have a return value here.
// Is it because if the an exception occurs the codes in try stops and doesn't get to the return value?
}
catch(NumberFormatException e)
{
e.printStackTrace();
}
catch(RangeException e)
{
throw e;
}
finally
{
System.out.println("Thank you for using the program!");
//so would I need to put a return value of type double here?
}
}
}
My question is, how do you return a value when you are using try
and catch
?
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