Welcome to OStack Knowledge Sharing Community for programmer and developer-Open, Learning and Share
Welcome To Ask or Share your Answers For Others

Categories

0 votes
486 views
in Technique[技术] by (71.8m points)

sql server - Group by every N records in T-SQL

I have some performance test results on the database, and what I want to do is to group every 1000 records (previously sorted in ascending order by date) and then aggregate results with AVG.

I'm actually looking for a standard SQL solution, however any T-SQL specific results are also appreciated.

The query looks like this:

SELECT TestId,Throughput  FROM dbo.Results ORDER BY id
See Question&Answers more detail:os

与恶龙缠斗过久,自身亦成为恶龙;凝视深渊过久,深渊将回以凝视…
Welcome To Ask or Share your Answers For Others

1 Answer

0 votes
by (71.8m points)
WITH T AS (
  SELECT RANK() OVER (ORDER BY ID) Rank,
    P.Field1, P.Field2, P.Value1, ...
  FROM P
)
SELECT (Rank - 1) / 1000 GroupID, AVG(...)
FROM T
GROUP BY ((Rank - 1) / 1000)
;

Something like that should get you started. If you can provide your actual schema I can update as appropriate.


与恶龙缠斗过久,自身亦成为恶龙;凝视深渊过久,深渊将回以凝视…
Welcome to OStack Knowledge Sharing Community for programmer and developer-Open, Learning and Share
Click Here to Ask a Question

...