Welcome to OStack Knowledge Sharing Community for programmer and developer-Open, Learning and Share
Welcome To Ask or Share your Answers For Others

Categories

0 votes
937 views
in Technique[技术] by (71.8m points)

sqlite - Aggregate difference between DateTime fields in Django

I have a table containing a series of entries which relate to time periods (specifically, time worked for a client):

task_time:
id     |    start_time    |    end_time       |    client (fk)
1        08/12/2011 14:48   08/12/2011 14:50     2

I am trying to aggregate all the time worked for a given client, from my Django app:

time_worked_aggregate = models.TaskTime.objects.
                        filter(client = some_client_id).
                        extra(select = {'elapsed': 'SUM(task_time.end_time - task_time.start_time)'}).
                        values('elapsed')

if len(time_worked_aggregate) > 0:
    time_worked = time_worked_aggregate[0]['elapsed'].total_seconds()
else:
    time_worked = 0

This seems inelegant, but it does work. Or at least so I thought: it turns out that it works fine on a PostgreSQL database, but when I move over to SQLite, everything dies.

A bit of digging suggests that the reason for this is that DateTimes aren't first-class data in SQLite. The following raw SQLite query will do my job:

SELECT SUM(strftime('%s', end_time) - strftime('%s', start_time)) FROM task_time WHERE ...;

My question is as follows:

  • The Python sample above seems roundabout. Can we do this more elegantly?
  • More importantly at this stage, can we do it in a way that will work on both Postgres and SQLite? Ideally, I'd like not to be writing raw SQL queries and switching on the database backend that happens to be in place; in general, Django is extremely good at protecting us from this. Does Django have a reasonable abstraction for this operation? If not, what's a sensible way for me to do a conditional switch on the backend?

I should mention for context that the dataset is many thousands of entries; the following is not really practical:

sum([task_time.end_date - task_time.start_date for task_time in models.TaskTime.objects.filter(...)])
See Question&Answers more detail:os

与恶龙缠斗过久,自身亦成为恶龙;凝视深渊过久,深渊将回以凝视…
Welcome To Ask or Share your Answers For Others

1 Answer

0 votes
by (71.8m points)

Almost the same solution as @andri proposed. In the final result you will get the same data. ExpressionWrapper - New in Django 1.8.

from datetime import timedelta
from django.db.models import ExpressionWrapper, F, fields
from app.models import MyModel

duration = ExpressionWrapper(F('closed_at') - F('opened_at'), output_field=fields.DurationField())
objects = MyModel.objects.closed().annotate(duration=duration).filter(duration__gt=timedelta(seconds=2))

for obj in objects:
    print obj.id, obj.duration, obj.duration.seconds

# sample output
# 807 0:00:57.114017 57
# 800 0:01:23.879478 83
# 804 3:40:06.797188 13206
# 801 0:02:06.786300 126

与恶龙缠斗过久,自身亦成为恶龙;凝视深渊过久,深渊将回以凝视…
Welcome to OStack Knowledge Sharing Community for programmer and developer-Open, Learning and Share
Click Here to Ask a Question

...