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linux - Cross-platform way to open a file using Java 1.5

I'm using Java 1.5 and I'd like to launch the associated application to open the file. I know that Java 1.6 introduced the Desktop API, but I need a solution for Java 1.5.

So far I found a way to do it in Windows:

Runtime.getRuntime().exec(new String[]{ "rundll32", 
                          "url.dll,FileProtocolHandler", fileName });

Is there a cross-platform way to do it? Or at least a similar solution for Linux?

See Question&Answers more detail:os

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public static boolean isWindows() {
    String os = System.getProperty("os.name").toLowerCase();
    return os.indexOf("windows") != -1 || os.indexOf("nt") != -1;
}
public static boolean isMac() {
    String os = System.getProperty("os.name").toLowerCase();
    return os.indexOf("mac") != -1;
}
public static boolean isLinux() {
    String os = System.getProperty("os.name").toLowerCase();
    return os.indexOf("linux") != -1;
}
public static boolean isWindows9X() {
    String os = System.getProperty("os.name").toLowerCase();
    return os.equals("windows 95") || os.equals("windows 98");
}

and

 if (isLinux())
  {
     cmds.add(String.format("gnome-open %s", fileName));
     String subCmd = (exec) ? "exec" : "openURL";
     cmds.add(String.format("kfmclient "+subCmd+" %s", fileName));
  }
  else if (isMac())
  {
     cmds.add(String.format("open %s", fileName));
  }
  else if (isWindows() && isWindows9X())
  {
     cmds.add(String.format("command.com /C start %s", fileName));
  }
  else if (isWindows())
  {
     cmds.add(String.format("cmd /c start %s", fileName));
  }

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