Welcome to OStack Knowledge Sharing Community for programmer and developer-Open, Learning and Share
Welcome To Ask or Share your Answers For Others

Categories

0 votes
253 views
in Technique[技术] by (71.8m points)

java - Right Shift to Perform Divide by 2 On -1

I know that I can perform divide by 2 using right shift.

For simplicity, take a 4 bit number system

-1 - 1111
-2 - 1110
-3 - 1101
-4 - 1100
-5 - 1011
-6 - 1010
-7 - 1001
-8 - 1000
7  - 0111
6  - 0110
5  - 0101
4  - 0100
3  - 0011
2  - 0010
1  - 0001
0  - 0000

If I try to perform

6 / 2 = 0110 >> 1 = 0011 = 3
-6/ 2 = 1010 >> 1 = 1101 = -3

Is valid for both +ve and -ve number

However, when come to 1

1 / 2 = 0001 >> 1 = 0000 = 0
-1/ 2 = 1111 >> 1 = 1111 = -1

Seems like there is a special case in -1, as right shift then to move it to negative infinity.

Currently, I need to put a special if check for this, as I am expecting -1 / 2 = 0.

I was wondering how do you guy handle this exception in your code? You guy put an if check?

See Question&Answers more detail:os

与恶龙缠斗过久,自身亦成为恶龙;凝视深渊过久,深渊将回以凝视…
Welcome To Ask or Share your Answers For Others

1 Answer

0 votes
by (71.8m points)

Any negative odd number won't work. However to answer your question, if you know you can have negative numbers, just divide by 2. This is turned into a shift with a fixup by the jit/compiler.


与恶龙缠斗过久,自身亦成为恶龙;凝视深渊过久,深渊将回以凝视…
Welcome to OStack Knowledge Sharing Community for programmer and developer-Open, Learning and Share
Click Here to Ask a Question

...