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javascript：if在条件为false的情况下仍然执行代码是为什么？

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javascript：if在条件为false的情况下仍然执行代码是为什么？

条件为changeNum !== undefined && changeNumIndex !== undefined,
p1为执行成功的现象，p2为我复制条件过去重新执行，但是发现执行失败。
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findIndex返回-1不是undefined。你这是chrome的调试？


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