java - Regular Expression for Percentage of marks

Question

I am trying to create a regex that matches percentage for marks

For example if we consider few percentages

1)100%
2)56.78%
3)56 78.90%
4)34.6789%

The matched percentages should be

100%
56.78%
34.6789%

I have made an expression "\d.+[\d]%" but it also matches for 56 78.90% which I don't want.

If anyone knows such expression please share

Answer 1

\d+(?:\.\d+)?%

This should do it for you.

For more stringent test use,

(?<!.)(?!0+(?:.0+)?%)(?:d|[1-9]d|100)(?:(?<!100).d+)?%

See demo.

https://regex101.com/r/zsNIrG/2