Declare the template argument of the std::initializer_list
as having type std::pair<const int, int>
Here is a demonstrative program
#include <iostream>
#include <map>
#include <initializer_list>
class Test {
std::map<int, int> m_ints;
public:
Test(std::initializer_list<std::pair<const int, int>> init):
m_ints(init)
{}
};
int main()
{
Test t = { { 1, 2 }, { 2, 3 } };
return 0;
}
The corresponding constructor is declared the following way
map( initializer_list<value_type>,
const Compare& = Compare(),
const Allocator& = Allocator());
and value_type is defined like
typedef pair<const Key, T> value_type;
Thus you could define the constructor of your class also the following way
Test( std::initializer_list<std::map<int, int>::value_type> init ) :
m_ints(init)
{}
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