Welcome to OStack Knowledge Sharing Community for programmer and developer-Open, Learning and Share
Welcome To Ask or Share your Answers For Others

Categories

0 votes
444 views
in Technique[技术] by (71.8m points)

actionscript 3 - Unexpected Flash Security Exception When Using URLLoader

What I am trying to accomplish is to upload some binary data, specifically a ByteArray representing a PNG image, to a server using the URLLoader class in conjunction with URLRequest.

When I set the contentType property of the URLRequest to 'multipart/form-data' instead of the default, the call to urlLoader.load() results in a security exception.

When I leave the contentType property as the default, it works fine, but takes a long time (proportional to the length of the PNG file) to upload the file to the server.

So, my question is WHY am I getting this security exception? And how can I avoid it?

Note that my SWF is being served up from a development server, not the local filesystem (the Google App Engine development server to be precise).

Here is the code:

var pngFile:ByteArray = PNGEncoder.encode(bitmapData);

var urlRequest:URLRequest = new URLRequest('/API/uploadImage');

// With this line of code, the call to urlLoader.load() throws the following security exception:
// 'SecurityError: Error #2176: Certain actions, such as those that display a pop-up window, may only be invoked upon user interaction, for example by a mouse click or button press.'
urlRequest.contentType = 'multipart/form-data';

urlRequest.method = URLRequestMethod.POST;
urlRequest.data = pngFile;
urlRequest.requestHeaders.push(new URLRequestHeader('Cache-Control', 'no-cache'));

urlLoader = new URLLoader();
urlLoader.dataFormat = URLLoaderDataFormat.TEXT;
urlLoader.addEventListener(Event.COMPLETE, onUploadComplete);
urlLoader.addEventListener(IOErrorEvent.IO_ERROR, onUploadError);

NextFrame.addCallback(function () {
    urlLoader.load(urlRequest);
});
See Question&Answers more detail:os

与恶龙缠斗过久,自身亦成为恶龙;凝视深渊过久,深渊将回以凝视…
Welcome To Ask or Share your Answers For Others

1 Answer

0 votes
by (71.8m points)

It could be possible that contentType does not refer to what data you send, but to what data you receive. Try to set the requestHeaders, that should work:

urlRequest.requestHeaders.push(new URLRequestHeader('Content-type', 'multipart/form-data'));

Also, I've found a piece of code where in one of my projects. The code works and sends some binary JPEG data to the server, using POST. I dit it some time ago and I can't explain why I did the things this way, but maybe it helps. I'm pasting it as is:

function sendData(submitPath:String, descriere:String):void {
    // building the url request for uploading the jpeg to the server
    var header:URLRequestHeader = new URLRequestHeader('Content-type', 'application/octet-stream');
    var jpgURLRequest:URLRequest = new URLRequest(submitPath+'/id/'+player.id+'/path/'+player.contentPath.replace('/','')+'/width/'+player.videoWidth+'/height/'+player.videoHeight+'/descriere/'+descriere+'/timp/'+time);
    jpgURLRequest.requestHeaders.push(header);
    jpgURLRequest.method = URLRequestMethod.POST;
    jpgURLRequest.data = screenShot;

    // sending the data to the server
    var sender:URLLoader = new URLLoader();
    sender.load(jpgURLRequest);
}

与恶龙缠斗过久,自身亦成为恶龙;凝视深渊过久,深渊将回以凝视…
Welcome to OStack Knowledge Sharing Community for programmer and developer-Open, Learning and Share
Click Here to Ask a Question

...