Welcome to OStack Knowledge Sharing Community for programmer and developer-Open, Learning and Share
Welcome To Ask or Share your Answers For Others

Categories

0 votes
551 views
in Technique[技术] by (71.8m points)

c# - Problem with Generic Linq OrderBy function

I saw the following function in a posting which allows one to order data using a generic expression:

public static IOrderedQueryable<T> OrderBy<T, TKey>(
  this IQueryable<T> source, Expression<Func<T, TKey>> func, bool isDescending) {
  return isDescending ? source.OrderByDescending(func) : source.OrderBy(func);
}

When I try to use this function I get an error saying "The type or namespace name "TKey' could not be found (are you missing a using directive or an assembly reference?)". I'm doing something dumb here but I can't figure it out.

Edit:

After doing a bit more research, I think my problem is in building the Expression that I pass into it. Is it possible to build an expression that can contain different types? Let's say my dataset has a string, an int, and a bool and I want to use the generic function above to sort by any of the items. How do I do this?

I have this working now:

if (IsString)
{
   Expression<Func<T, string>> expString = ...;
   // call orderBy with expString
}
else if (IsInt)
{
   Expression<Func<T, int>> expInt;
   // call orderBy w/ expInt
}
:

I want something like:

Expression<Func<T, {something generic!}>> exp;
if (IsString)
    exp = ...;
else if (IsInt)
    exp = ...;
:
// call orderBy with exp
See Question&Answers more detail:os

与恶龙缠斗过久,自身亦成为恶龙;凝视深渊过久,深渊将回以凝视…
Welcome To Ask or Share your Answers For Others

1 Answer

0 votes
by (71.8m points)

One quick observation: You don't really need to use a lambda expression (Expression<Func<T,TKey>>). A simple delegate (Func<T,TKey>) is fine.

That said, I think the answer you might be looking for is this:

Func<T,IComparable> func = null;
if (IsString)
    func = (T a) => a.SomeStringValue;
else if (IsInt)
    func = (T a) => a.SomeIntValue;
// call orderBy with exp

与恶龙缠斗过久,自身亦成为恶龙;凝视深渊过久,深渊将回以凝视…
Welcome to OStack Knowledge Sharing Community for programmer and developer-Open, Learning and Share
Click Here to Ask a Question

...