Welcome to OStack Knowledge Sharing Community for programmer and developer-Open, Learning and Share
Welcome To Ask or Share your Answers For Others

Categories

0 votes
698 views
in Technique[技术] by (71.8m points)

ios - How to check if a character is supported by a font

I'm working on an app with a text field. The text wrote in this field will be printed and I have an issue with some characters like emoji, chinese characters, etc... because the font do not provide these characters.

It's why I want to get all the character provided by a font (The font is downloaded so I can deal directly with the file or with an UIFont object).

I heard about CTFontGetGlyphsForCharacters but I'm not sure that this function do what I want and I can't get it work.

Here is my code :

CTFontRef fontRef = CTFontCreateWithName((CFStringRef)font.fontName, font.pointSize, NULL);
NSString *characters = @"??"; // emoji character
NSUInteger count = characters.length;
CGGlyph glyphs[count];
if (CTFontGetGlyphsForCharacters(fontRef, (const unichar*)[characters cStringUsingEncoding:NSUTF8StringEncoding], glyphs, count) == false)
    NSLog(@"CTFontGetGlyphsForCharacters failed.");

Here CTFontGetGlyphsForCharacters return false. It's what I want because the character '??' is not provided by the font used.
The problem is when I replace NSString *characters = @"??" by NSString *characters = @"abc", CTFontGetGlyphsForCharacters return again false. Obviously, my font provide a glyph for all the ASCII characters.

See Question&Answers more detail:os

与恶龙缠斗过久,自身亦成为恶龙;凝视深渊过久,深渊将回以凝视…
Welcome To Ask or Share your Answers For Others

1 Answer

0 votes
by (71.8m points)

I finally solve it :

- (BOOL)isCharacter:(unichar)character supportedByFont:(UIFont *)aFont
{
    UniChar characters[] = { character };
    CGGlyph glyphs[1] = { };
    CTFontRef ctFont = CTFontCreateWithName((CFStringRef)aFont.fontName, aFont.pointSize, NULL);
    BOOL ret = CTFontGetGlyphsForCharacters(ctFont, characters, glyphs, 1);
    CFRelease(ctFont);
    return ret;
}

与恶龙缠斗过久,自身亦成为恶龙;凝视深渊过久,深渊将回以凝视…
Welcome to OStack Knowledge Sharing Community for programmer and developer-Open, Learning and Share
Click Here to Ask a Question

...