syntax error - LibCurl CURLOPT_URL not accepting string? C++

Question

So basically what I want to do is use libcurl to fetch slightly different urls, e.g.:

http://foo.com/foo.asp?name=*NAMEHERE*

What I would like to do is iterate through a vector of names and get each one, e.g.:

http://foo.com/foo.asp?name=James

Then

http://foo.com/foo.asp?name=Andrew

And so on.

However, when I try doing this:

int foo (){
    CURL *curl;
    CURLcode success;
    char errbuf[CURL_ERROR_SIZE];
    int m_timeout = 15;

    if ((curl = curl_easy_init()) == NULL) {
        perror("curl_easy_init");
        return 1;
    }

    std::vector<std::string> names;

    names.push_back("James");
    names.push_back("Andrew");

    for (std::vector<std::string>::const_iterator i = names.begin(); i != names.end(); ++i){
        curl_easy_setopt(curl, CURLOPT_ERRORBUFFER, errbuf);
        curl_easy_setopt(curl, CURLOPT_VERBOSE, 1L);

        curl_easy_setopt(curl, CURLOPT_TIMEOUT, long(m_timeout));
        curl_easy_setopt(curl, CURLOPT_URL, "http://foo.com/foo.asp?name=" + *i);
        curl_easy_setopt(curl, CURLOPT_COOKIEFILE, "cookies.txt");
        curl_easy_setopt(curl, CURLOPT_COOKIEJAR, "cookies.txt");
        curl_easy_setopt(curl, CURLOPT_FOLLOWLOCATION, 1L);
        curl_easy_setopt(curl, CURLOPT_AUTOREFERER, 1L);
    }

    if ((success = curl_easy_perform(curl)) != 0) {
        fprintf(stderr, "%s: %s
", "curl_easy_perform", errbuf);
        return 1;
    }

    curl_easy_cleanup(curl);

    return 0;
}

It gives me an error:

Cannot pass object of non-trivial type 'std::__1::basic_string<char>' through variadic function; call will abort at runtime

On this line:

curl_easy_setopt(curl, CURLOPT_URL, "http://foo.com/foo.asp?name=" + *i);

because of the + *i.

Is what I want to do possible? Is there a solution?

EDIT: Thanks for the answer, but for some reason, when I run this it only gets the website with the last string in the vector, and it ignores the other ones. In my case, it skips James and goes straight to Andrew. Why does that happen?

Answer 1

The parameter passed to curl_easy_setopt for CURLOPT_URL needs to be a char * instead of a std::string. You can get a const char * from a std::string by calling its c_str member function:

std::string url = "http://foo.com/foo.asp?name=" + *i;
curl_easy_setopt(curl, CURLOPT_URL, url.c_str());

For anyone who ends up here in the future, take a look at the curl manual if you haven't already. There's also an online book.

The documentation for curl_easy_setopt says you need to read about a specific option to know what parameter type to use.

All options are set with an option followed by a parameter. That parameter can be a long, a function pointer, an object pointer or a curl_off_t, depending on what the specific option expects. Read this manual carefully as bad input values may cause libcurl to behave badly!

The documentation for CURLOPT_URL says exactly what the parameter type needs to be.

Pass in a pointer to the URL to work with. The parameter should be a char * to a zero terminated string which must be URL-encoded in the following format:

scheme://host:port/path