Welcome to OStack Knowledge Sharing Community for programmer and developer-Open, Learning and Share
Welcome To Ask or Share your Answers For Others

Categories

0 votes
679 views
in Technique[技术] by (71.8m points)

sql - PostgreSQL use value from previous row if missing

I have a following query:

WITH t as (
  SELECT date_trunc('hour', time_series) as trunc 
  FROM generate_series('2013-02-27 22:00'::timestamp, '2013-02-28 2:00', 
                       '1 hour') as time_series
  GROUP BY trunc
  ORDER BY trunc
)
SELECT DISTINCT ON(trunc) trunc, id
FROM t
LEFT JOIN (
   SELECT id, created, date_trunc('hour', created) as trunc_u
   FROM event
   ORDER BY created DESC
) u
ON trunc = trunc_u

which yields the following result:

"2013-02-27 22:00:00";
"2013-02-27 23:00:00";2
"2013-02-28 00:00:00";5
"2013-02-28 01:00:00";
"2013-02-28 02:00:00";

Table event has id, created and some other columns, but only those are relevant here. The query above gives me id of last event generated per given trunc time period (thanks to DISTINCT ON I get a nice aggregation per period).

Now, this query yields NULL if no events happened in given time period. I would like it to return the previous available id, even if it is from different time period. I.e.:

"2013-02-27 22:00:00";0
"2013-02-27 23:00:00";2
"2013-02-28 00:00:00";5
"2013-02-28 01:00:00";5
"2013-02-28 02:00:00";5

I am sure I am missing some easy way to accomplish this. Any advice?

See Question&Answers more detail:os

与恶龙缠斗过久,自身亦成为恶龙;凝视深渊过久,深渊将回以凝视…
Welcome To Ask or Share your Answers For Others

1 Answer

0 votes
by (71.8m points)

You ca mix a self join and windows functions

Simplifying I take this table with this sample values:

create table t ( a int, b int);    
insert into t values 
( 1, 1),
( 2, Null),
( 3, Null),
( 4, 2 ),
( 5, Null),
( 6, Null);

In your query a is trunc_u and b is your id. The query is:

with cte as (    
    select 
      t1.a, 
      coalesce( t1.b, t2.b, 0) as b,
      rank() OVER 
       (PARTITION BY t1.a ORDER BY t2.a DESC) as pos
    from t t1 
    left outer join t t2
      on t2.b is not null and
         t2.a < t1.a    
)
select a, b
from cte
where pos = 1;

And results:

| A | B |
---------
| 1 | 1 |
| 2 | 1 |
| 3 | 1 |
| 4 | 2 |
| 5 | 2 |
| 6 | 2 |

与恶龙缠斗过久,自身亦成为恶龙;凝视深渊过久,深渊将回以凝视…
Welcome to OStack Knowledge Sharing Community for programmer and developer-Open, Learning and Share
Click Here to Ask a Question

...