Can this possibly be done via a pure SQL query or do I have to use some php logic?
Yes, it is better to create a Numbers table (single column N) that contains nothing but the numbers 0 to 999. It can be used for many things, not least a query like the below:
SELECT COUNT(t.click_date) as clicks,
DATE_FORMAT(adddate($start_date, interval N day), '%d %M %Y') as point
FROM Numbers
LEFT JOIN tracking t
ON t.click_date >= adddate($start_date, interval N day)
and t.click_date < adddate($start_date, interval (N+1) day)
WHERE N between 0 and datediff($start_date, $end_date)
GROUP BY N
Btw, why do I have 0 February 2011 as my first date
You're using the wrong format. It's UPPER case W not lower for day-of-week, so '%W %M %Y' or '%d %M %Y' for day-of-month.
http://dev.mysql.com/doc/refman/5.5/en/date-and-time-functions.html#function_date-format
maybe my GROUP BY isn't working correctly?
You are using GROUP BY DAY(FROM_UNIXTIME(click_date))
note "day" not weekday, but you are displaying (or trying to) "%W" (weekday) - pick one, don't mix them.
EDIT: If you prefer not to materialize (create as a real table) a Numbers sequence table, you can construct one on the fly. It won't be pretty.
Note: N1, N2 and N3 below combine to give a possible range of 0-999
SELECT COUNT(t.click_date) as clicks,
DATE_FORMAT(adddate($start_date, interval N day), '%d %M %Y') as point
FROM (
select N1 * 100 + N2 * 10 + N3 as N
from (
select 0 N1 union all select 1 union all select 2 union all
select 3 union all select 4 union all select 5 union all
select 6 union all select 7 union all
select 8 union all select 9) N1
cross join (
select 0 N2 union all select 1 union all select 2 union all
select 3 union all select 4 union all select 5 union all
select 6 union all select 7 union all
select 8 union all select 9) N2
cross join (
select 0 N3 union all select 1 union all select 2 union all
select 3 union all select 4 union all select 5 union all
select 6 union all select 7 union all
select 8 union all select 9) N3
) Numbers
LEFT JOIN tracking t
ON t.click_date >= adddate($start_date, interval N day)
and t.click_date < adddate($start_date, interval (N+1) day)
WHERE N between 0 and datediff($start_date, $end_date)
GROUP BY N
EDIT #2: A straight Dates table
Put this in a new window in phpMyAdmin or run it as a batch. It creates a table named Dates, with every single date from day 1900-01-01
(or change in the script) to 2300-01-01
(or change).
DROP PROCEDURE IF EXISTS FillDateTable;
delimiter //
CREATE PROCEDURE FillDateTable()
LANGUAGE SQL
NOT DETERMINISTIC
CONTAINS SQL
SQL SECURITY DEFINER
COMMENT ''
BEGIN
drop table if exists datetable;
create table datetable (thedate datetime primary key, isweekday smallint);
SET @x := date('1900-01-01');
REPEAT
insert into datetable (thedate, isweekday) SELECT @x, case when dayofweek(@x) in (1,7) then 0 else 1 end;
SET @x := date_add(@x, interval 1 day);
UNTIL @x > date('2300-01-01') END REPEAT;
END//
delimiter ;
CALL FillDateTable;
With such a utility table, your query can be just
SELECT COUNT(t.click_date) as clicks,
DATE_FORMAT(thedate, '%d %M %Y') as point
FROM Dates
LEFT JOIN tracking t
ON t.click_date >= thedate
and t.click_date < adddate(thedate, interval 1 day)
WHERE thedate between $start_date and $end_date
GROUP BY thedate