Welcome to OStack Knowledge Sharing Community for programmer and developer-Open, Learning and Share
Welcome To Ask or Share your Answers For Others

Categories

0 votes
855 views
in Technique[技术] by (71.8m points)

node.js - return document with latest subdocument only in mongodb aggregate

I've got these Mongoose Schemas:

var Thread = new Schema({
    title: String, messages: [Message]
});
var Message = new Schema({
    date_added: Date, author: String, text: String
});

How do you return all Threads with their latest Message subdocument (limit 1) ?

Currently, I'm filtering the Thread.find() results on the server side but I'd like to move this operation in MongoDb using aggregate() for performance matters.

See Question&Answers more detail:os

与恶龙缠斗过久,自身亦成为恶龙;凝视深渊过久,深渊将回以凝视…
Welcome To Ask or Share your Answers For Others

1 Answer

0 votes
by (71.8m points)

You can use $unwind, $sort, and $group to do this using something like:

Thread.aggregate([
    // Duplicate the docs, one per messages element.
    {$unwind: '$messages'}, 
    // Sort the pipeline to bring the most recent message to the front
    {$sort: {'messages.date_added': -1}}, 
    // Group by _id+title, taking the first (most recent) message per group
    {$group: {
        _id: { _id: '$_id', title: '$title' }, 
        message: {$first: '$messages'}
    }},
    // Reshape the document back into the original style
    {$project: {_id: '$_id._id', title: '$_id.title', message: 1}}
]);

与恶龙缠斗过久,自身亦成为恶龙;凝视深渊过久,深渊将回以凝视…
Welcome to OStack Knowledge Sharing Community for programmer and developer-Open, Learning and Share
Click Here to Ask a Question

...