sed delete lines between two patterns, without the second pattern, including the first pattern

Question

my input file looks like this:

[1234]
text 
text
text

[3456]
text 
text
text

[7458]
text 
text
text

I want to delete all lines between the patterns, including FROM_HERE and excluding TO_HERE.

sed '/FROM_HERE/,/TO_HERE/{//p;d;}'

Now i have:

sed '/^['"3456"']/,/^[.*]/{//p;d;}'

but this command does not delete the line FROM_HERE too. for 3456 at the end the input file should look like:

[1234]
text 
text
text

[7458]
text 
text
text

How can i achieve this? Thanks.

Answer 1

You could delete lines from your pattern to next blank line:

sed '/^['"3456"']/,/^$/{d;}' file