To find the angle formed by three points, you can use the dot product. Say you have the three points set up like this:
dot1
/
A /
/
/ theta
dot2-------dot3
B
I assume you want to find the angle theta
between the lines created by points dot1
, dot2
and dot3
, where they're points that you've collected from the user. Then, you can define two vectors A
and B
:
A = dot1 - dot2
B = dot3 - dot2
Subtraction of two points simply means that you subtract each corresponding component. So it might look like this in code:
// I'll just use another point to represent a vector
Point A = new Point();
A.X = dot1.X - dot2.X;
A.Y = dot1.Y - dot2.Y;
Point B = new Point();
B.X = dot3.X - dot2.X;
B.Y = dot3.Y - dot2.Y;
The angle between these two vectors as defined by the dot product is:
A * B
theta = acos(-----------)
||A|| ||B||
Where ||A||
and ||B||
are the lengths of the vectors A
and B
respectively, which is the square root of the sum of the squares of the components (which is simply the distance formula).
double ALen = Math.Sqrt( Math.Pow(A.X, 2) + Math.Pow(A.Y, 2) );
double BLen = Math.Sqrt( Math.Pow(B.X, 2) + Math.Pow(B.Y, 2) );
The dot product A * B
is simply the sum of the products of the components, so it might look like this in code:
double dotProduct = A.X * B.X + A.Y * B.Y;
So you may perhaps have a dot product defined like this:
double theta = (180/Math.PI) * Math.Acos(dotProduct / (ALen * BLen));
This gives you the angle in degrees (remember that Math.Acos()
returns the angle in radians).
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