c - why we do not use '&' in scanf for char arrray

Question

int age;
char name[10];

scanf("%d", &age);
scanf("%s", name);

In first scanf function we use '&' symbol before age, but in second scanf we don't use '&' as it is a char array. Can anybody tell me why is so?

Answer 1

Because the array is already passed as an address, whereas the integer variable is not (and thus explicitly needs its address passed via the & address-of operator).