ios - How do I unwrap an Optional when pattern matching tuples in Swift?

Question

In Swift, there's a common if let pattern used to unwrap optionals:

if let value = optional {
    print("value is now unwrapped: (value)")
}

I'm currently doing this kind of pattern matching, but with tuples in a switch case, where both params are optionals:

//url is optional here
switch (year, url) {
    case (1990...2015, let unwrappedUrl):
        print("Current year is (year), go to: (unwrappedUrl)")
}       

However, this prints:

"Current year is 2000, go to Optional(www.google.com)"

Is there a way I can unwrap my optional and pattern match only if it's not nil? Currently my workaround is this:

switch (year, url) {
    case (1990...2015, let unwrappedUrl) where unwrappedUrl != nil:
        print("Current year is (year), go to: (unwrappedUrl!)")
}       

Answer 1

You can use the x? pattern:

case (1990...2015, let unwrappedUrl?):
    print("Current year is (year), go to: (unwrappedUrl)")

x? is just a shortcut for .some(x), so this is equivalent to

case (1990...2015, let .some(unwrappedUrl)):
    print("Current year is (year), go to: (unwrappedUrl)")