c++ - Initialisation of static class member. Why constexpr?

Question

when I want to have a static pointer as a member of a class I need constexprfor the initialisation with nullptr.

class Application {
    private:
        constexpr static Application* app = nullptr;
}

Can someone explain me why I need to do that? I cannot find the exact reason why it`s necessary that the static variable has to exist at compile time.

Answer 1

That's because you're initialising it inside the class definition. That's only allowed for constant integral and enumeration types (always) and for constexpr data members (since C++11). Normally, you'd initialise it where you define it (outside the class), like this:

Application.h

class Application {
    private:
        static Application* app;
}

Application.cpp

Application* Application::app = nullptr;

Note that you need to provide the out-of-class definition even in the constexpr case, but it must not contain an initialiser then. Still, I believe the second case is what you actually want.