java program using int and double

Question

I have written a simple Java program as shown here:

public class Test {

    public static void main(String[] args) {
        int i1 =2;
        int i2=5;
        double d = 3 + i1/i2 +2;
        System.out.println(d);
    }
}

Since variable d is declared as double I am expecting the result of this program is 5.4 but I got the output as 5.0

Please help me in understanding this.

Answer 1

i1/i2 will be 0. Since i1 and i2 are both integers.

If you have int1/int2, if the answer is not a perfect integer, the digits after the decimal point will be removed. In your case, 2/5 is 0.4, so you'll get 0.

You can cast i1 or i2 to double (the other will be implicitly converted)

double d = 3 + (double)i1/i2 +2;