php - How to get everything after the domain name into a string

Question

My goal is to get everything after the domain name into a string. As in mysite.com/page/page2 would result in a string "page/page2". That I can do, however it starts giving me problems when, for example, the site is in a subfolder and not in root, then the folder the site is in will also be included in the string and if I'm not using mod_rewrite to get pretty links, it will also add index.php to the string.

So, I would need a trick or two to make the script understand whether or not the site is in a subfolder such as mysite.com/sitefolder/page/page2 and that it would still result in a string

page/page2

If the site doesn not use mod_rewrite and the url is mysite.com/sitefolder/index.php/page/page2, it would still result in a string

page/page2

Keep in mind that I have URL and USE_MOD_REWRITE defined in a config file, so no need for magic. I just have no idea how to go about getting that string. I know I could do $_SERVER['REQUEST_URI'] to get the string, but then index.php would still be in it. I'm sorry if I didn't explain well enough, but all help is appreciated.

Answer 1

• get the path by parsing the request uri
• remove eventual script name from the end of the string (e.g. index.php)

• rtrim any trailing slashes

  $request = parse_url($_SERVER['REQUEST_URI']);
  $path = $request["path"];
  $result = rtrim(str_replace(basename($_SERVER['SCRIPT_NAME']), '', $path), '/');
  

EDIT

$request = parse_url($_SERVER['REQUEST_URI']);
$path = $request["path"];

$result = trim(str_replace(basename($_SERVER['SCRIPT_NAME']), '', $path), '/');

$result = explode('/', $result);
$max_level = 2;
while ($max_level < count($result)) {
    unset($result[0]);
}
$result = '/'.implode('/', $result);