Welcome to OStack Knowledge Sharing Community for programmer and developer-Open, Learning and Share
Welcome To Ask or Share your Answers For Others

Categories

0 votes
605 views
in Technique[技术] by (71.8m points)

javascript, $.ajax, variable name

I'm trying to iterate over an array and assign a variable with a for loop. So something like this:

function Person(name, status){
  this.name = name;
  this.status = status;
}

var status = [];
var array = ["bill","bob","carl","ton"];
function exAjax(function(){
 for(var i = 0; i < array.length; i++){
   var name = array[i];
   console.log(name); =====> this gives the correct name

   $.ajax({
     url: xxxxxxx,
     success: function(data){
       if(data.stream === null){
         var person = new Person(name, "dead");
         console.log(name); =====> return undefined until the last
         person

         status.push(person);       
       }
     }

   })
   name = "";
 }
})

The problem I'm having is that name is not getting into the success function. I thought js keeps traveling upwards to look for the variable if it doesn't exist in it's current scope? I'm getting undefined for the name variable if I try to console.log name! Scope masters what am I doing wrong?

See Question&Answers more detail:os

与恶龙缠斗过久,自身亦成为恶龙;凝视深渊过久,深渊将回以凝视…
Welcome To Ask or Share your Answers For Others

1 Answer

0 votes
by (71.8m points)

You can use .queue(), $.map() to maintain scope of name. Also, change status array to an object having property status where value is an array to prevent possible conflict with this.status of Person object.

Note, you can also chain .promise(/* queueName */) to perform tasks at .then() when all queued functions in queueName, i.e.g., "status" have been called, queueName .length is 0.

function Person(name, status){
  this.name = name;
  this.status = status;
}

var blob = new Blob(['{"stream":null}'], {type:"application/json"});
var url = URL.createObjectURL(blob);
// change `status` array reference, e.g., to `arr`
var arr = {status:[]};
var array = ["bill","bob","carl","ton"];

$(arr).queue("status", $.map(array, function(curr) {
  return function(next) {
    var name = curr;
    // do asynchronous stuff
    $.ajax({url:url, dataType:"json"})
    .then(function(data) {
       if(data.stream == null){
         var person = new Person(name, "dead");
         console.log(name, person);
         arr.status.push(person);
       }
    })
    .then(next) // call next function in `"status"` queue
  }
}))
.dequeue("status")
.promise("status")
// do stuff when all functions in `"status"` queue have completed,
// `"status"` queue `.length` is `0`
.then(function() {
   // `this` : `arr` as jQuery object
   // `this[0].status`: array containing objects pushed to `arr.status`
   console.log(this[0].status); // $(this).prop("status");
});
<script src="https://ajax.googleapis.com/ajax/libs/jquery/2.1.1/jquery.min.js">
</script>

与恶龙缠斗过久,自身亦成为恶龙;凝视深渊过久,深渊将回以凝视…
Welcome to OStack Knowledge Sharing Community for programmer and developer-Open, Learning and Share
Click Here to Ask a Question

...