The outdated approach with FROM OPENXML
might be an option here. Check this answer.
At this link you'll find a function John Cappelletti posted from time to time, which will shred any XML (credits below the function's code).
But I'm not sure, what you are really trying to achieve... Why do you need the path? If you are interested in the values of all target nodes you might do something like this (deep search with //
does not need the exact XPath
)
SELECT t.value(N'(text())[1]','nvarchar(max)')
FROM @xml.nodes('//target') AS A(t);
If you really need all and everything you can check this:
CREATE FUNCTION [dbo].[udf-XML-Hier](@XML xml)
Returns Table
As Return
with cte0 as (
Select Lvl = 1
,ID = Cast(1 as int)
,Pt = Cast(NULL as int)
,Element = x.value('local-name(.)','varchar(150)')
,Attribute = cast('' as varchar(150))
,Value = x.value('text()[1]','varchar(max)')
,XPath = cast(concat(x.value('local-name(.)','varchar(max)'),'[' ,cast(Row_Number() Over(Order By (Select 1)) as int),']') as varchar(max))
,Seq = cast(1000000+Row_Number() over(Order By (Select 1)) as varchar(max))
,AttData = x.query('.')
,XMLData = x.query('*')
From @XML.nodes('/*') a(x)
Union All
Select Lvl = p.Lvl + 1
,ID = Cast( (Lvl + 1) * 1024 + (Row_Number() Over(Order By (Select 1)) * 2) as int ) * 10
,Pt = p.ID
,Element = c.value('local-name(.)','varchar(150)')
,Attribute = cast('' as varchar(150))
,Value = cast( c.value('text()[1]','varchar(max)') as varchar(max) )
,XPath = cast(concat(p.XPath,'/',c.value('local-name(.)','varchar(max)'),'[',cast(Row_Number() Over(PARTITION BY c.value('local-name(.)','varchar(max)') Order By (Select 1)) as int),']') as varchar(max) )
,Seq = cast(concat(p.Seq,' ',10000000+Cast( (Lvl + 1) * 1024 + (Row_Number() Over(Order By (Select 1)) * 2) as int ) * 10) as varchar(max))
,AttData = c.query('.')
,XMLData = c.query('*')
From cte0 p
Cross Apply p.XMLData.nodes('*') b(c)
)
, cte1 as (
Select R1 = Row_Number() over (Order By Seq),A.*
From (
Select Lvl,ID,Pt,Element,Attribute,Value,XPath,Seq From cte0
Union All
Select Lvl = p.Lvl+1
,ID = p.ID + Row_Number() over (Order By (Select NULL))
,Pt = p.ID
,Element = p.Element
,Attribute = x.value('local-name(.)','varchar(150)')
,Value = x.value('.','varchar(max)')
,XPath = p.XPath + '/@' + x.value('local-name(.)','varchar(max)')
,Seq = cast(concat(p.Seq,' ',10000000+p.ID + Row_Number() over (Order By (Select NULL)) ) as varchar(max))
From cte0 p
Cross Apply AttData.nodes('/*/@*') a(x)
) A
)
Select A.R1
,R2 = IsNull((Select max(R1) From cte1 Where Seq Like A.Seq+'%'),A.R1)
,A.Lvl
,A.ID
,A.Pt
,A.Element
,A.Attribute
,A.XPath
,Title = Replicate('|---',Lvl-1)+Element+IIF(Attribute='','','@'+Attribute)
,A.Value
From cte1 A
/*
Source: http://beyondrelational.com/modules/2/blogs/28/posts/10495/xquery-lab-58-select-from-xml.aspx
Taken from John Cappelletti: https://stackoverflow.com/a/42729851/5089204
Declare @XML xml='<person><firstname preferred="Annie" nickname="BeBe">Annabelle</firstname><lastname>Smith</lastname></person>'
Select * from [dbo].[udf-XML-Hier](@XML) Order by R1
*/
GO
DECLARE @xml XML=
'<log>
<clients>
<client>
<section name ="Apps">
<questions>
<groupone>
<question>
<target>Age</target>
</question>
<question>
<target> Height</target>
</question>
<question>
<target> Weight</target>
</question>
</groupone>
<grouptwo name = "exercise">
<wording>what is your name</wording>
<question>
<id>1</id>
<target>def</target>
</question>
</grouptwo>
</questions>
</section>
</client>
</clients>
</log>';
SELECT * FROM dbo.[udf-XML-Hier](@xml);
GO