Welcome to OStack Knowledge Sharing Community for programmer and developer-Open, Learning and Share
Welcome To Ask or Share your Answers For Others

Categories

0 votes
881 views
in Technique[技术] by (71.8m points)

matplotlib - Plotting the temperature distribution on a sphere with python

I have the following problem:

a have N points on a sphere specified by a array x, with x.shape=(N,3). This array contains their cartesian coordinates. Furthermore, at each point, I have a specified temperature. This quantity is saved in an array T, with T.shape=(N,).

Is there any straight forward way to map this temperature distribution into the plane using different colors?

If it simplifies the task, the position can also be given in polar coordinates (heta,phi).

See Question&Answers more detail:os

与恶龙缠斗过久,自身亦成为恶龙;凝视深渊过久,深渊将回以凝视…
Welcome To Ask or Share your Answers For Others

1 Answer

0 votes
by (71.8m points)

To plot your data, you can use Basemap. The only problem is, that both contour and contourf routines needs gridded data. Here is example with naive (and slow) IDW-like interpolation on sphere. Any comments are welcome.

import numpy as np
from mpl_toolkits.basemap import Basemap
import matplotlib.pyplot as plt

def cart2sph(x, y, z):
    dxy = np.sqrt(x**2 + y**2)
    r = np.sqrt(dxy**2 + z**2)
    theta = np.arctan2(y, x)
    phi = np.arctan2(z, dxy)
    theta, phi = np.rad2deg([theta, phi])
    return theta % 360, phi, r

def sph2cart(theta, phi, r=1):
    theta, phi = np.deg2rad([theta, phi])
    z = r * np.sin(phi)
    rcosphi = r * np.cos(phi)
    x = rcosphi * np.cos(theta)
    y = rcosphi * np.sin(theta)
    return x, y, z

# random data
pts = 1 - 2 * np.random.rand(500, 3)
l = np.sqrt(np.sum(pts**2, axis=1))
pts = pts / l[:, np.newaxis]
T = 150 * np.random.rand(500)

# naive IDW-like interpolation on regular grid
theta, phi, r = cart2sph(*pts.T)
nrows, ncols = (90,180)
lon, lat = np.meshgrid(np.linspace(0,360,ncols), np.linspace(-90,90,nrows))
xg,yg,zg = sph2cart(lon,lat)
Ti = np.zeros_like(lon)
for r in range(nrows):
    for c in range(ncols):
        v = np.array([xg[r,c], yg[r,c], zg[r,c]])
        angs = np.arccos(np.dot(pts, v))
        idx = np.where(angs == 0)[0]
        if idx.any():
            Ti[r,c] = T[idx[0]]
        else:
            idw = 1 / angs**2 / sum(1 / angs**2)
            Ti[r,c] = np.sum(T * idw)

# set up map projection
map = Basemap(projection='ortho', lat_0=45, lon_0=15)
# draw lat/lon grid lines every 30 degrees.
map.drawmeridians(np.arange(0, 360, 30))
map.drawparallels(np.arange(-90, 90, 30))
# compute native map projection coordinates of lat/lon grid.
x, y = map(lon, lat)
# contour data over the map.
cs = map.contourf(x, y, Ti, 15)
plt.title('Contours of T')
plt.show()

enter image description here


与恶龙缠斗过久,自身亦成为恶龙;凝视深渊过久,深渊将回以凝视…
Welcome to OStack Knowledge Sharing Community for programmer and developer-Open, Learning and Share
Click Here to Ask a Question

...