i am going through oracle docs for deadlock..
i found this code
public class Deadlock {
static class Friend {
private final String name;
public Friend(String name) {
this.name = name;
}
public String getName() {
return this.name;
}
public synchronized void bow(Friend bower) {
System.out.format("%s: %s"
+ " has bowed to me!%n",
this.name, bower.getName());
bower.bowBack(this);
}
public synchronized void bowBack(Friend bower) {
System.out.format("%s: %s"
+ " has bowed back to me!%n",
this.name, bower.getName());
}
}
public static void main(String[] args) {
final Friend alphonse =
new Friend("Alphonse");
final Friend gaston =
new Friend("Gaston");
new Thread(new Runnable() {
public void run() { alphonse.bow(gaston); }
}).start();
new Thread(new Runnable() {
public void run() { gaston.bow(alphonse); }
}).start();
}
}
I am failing to understand, in what case deadlock will happen?
I run this code, it works fine. So there must be some special event, when deadlock will happen?
Suppose bow is called on alphonse
object first, will it leave its lock on alphonse
object when bower.bowBack(this)
is called on bower object?
Because if it retains its lock, bow
function on another object will not get lock until alphonse
leave its lock, and it will never be a deadlock situation..
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