c++ - Passing temporary object as parameter by value - is copy constructor called?

Question

If a have a class with both standard and copy constructors

class Ex{
       //constructor definitions
}

and a function that takes it as an argument (by value)

void F(Ex _exin){...}

take the following piece of code:

Ex A;
F(A);   //F's parameter is copy constructed from A
F(Ex());  //F's parameter uses the default constructor

In the third line I'm passing to F a new (temporary) object of the Ex class using the default constructor. My question is: after this new object is created is it also copy constructed/assigned (like it happens in the second line) or is it directly created "inside" F?

Answer 1

It was hard to find, but honestly it was bugging me. This is called copy constructor elision.

The standard illustrates this example:

class X{
public:
   X(int);
   X(const X&);
   ~X()
};

X f(X);

void g()
{
   X a(1);
   X b = f(X(2)); //identical to what you have:
   a = f(a);
}

And it states:

12.2/2 Temporary objects

Here, an implementation might use a temporary in which to construct X(2) before passing it to f() using X's copy-constructor; alternatively, X(2) might be constructed in the space used to hold the argument. /.../

After this the standard explains return value optimization, which is basically the same thing.

So it actually has nothing to do with observed behavior, it is up to the compiler.