c - 如何在C中将整数转换为字符串？ [重复](How to convert integer to string in C? [duplicate])

Question

This question already has an answer here:

(这个问题在这里已有答案：)

• How to convert an int to string in C?

  (如何在C中将int转换为字符串？)

  10 answers

  (10个答案)

I tried this example:

(我试过这个例子：)

/* itoa example */
#include <stdio.h>
#include <stdlib.h>

int main ()
{
    int i;
    char buffer [33];
    printf ("Enter a number: ");
    scanf ("%d",&i);
    itoa (i,buffer,10);
    printf ("decimal: %s
",buffer);
    itoa (i,buffer,16);
    printf ("hexadecimal: %s
",buffer);
    itoa (i,buffer,2);
    printf ("binary: %s
",buffer);
    return 0;
}

but the example there doesn't work (it says the function itoa doesn't exist).

(但那里的例子不起作用（它表示itoa不存在的功能）。)

  ask by janko-m translate from so

Answer 1

Use sprintf() :

(使用sprintf() ：)

int someInt = 368;
char str[12];
sprintf(str, "%d", someInt);

All numbers that are representable by int will fit in a 12-char-array without overflow, unless your compiler is somehow using more than 32-bits for int .

(所有可由int表示的数字都将适合12-char数组而不会溢出，除非您的编译器以某种方式使用超过32位的int 。)

When using numbers with greater bitsize, eg long with most 64-bit compilers, you need to increase the array size—at least 21 characters for 64-bit types.

(当使用具有更大位数的数字时，例如对于大多数64位编译器来说long ，则需要增加数组大小 - 对于64位类型，至少需要21个字符。)