c++ - Returning a reference to a local or temporary variable

Question

(This question already has answers here): question from:https://stackoverflow.com/questions/2744264/returning-a-reference-to-a-local-or-temporary-variable

Answer 1

You got lucky. Returning from the function doesn't immediately wipe the stack frame you just exited.

BTW, how did you confirm that you got a 6 back? The expression std::cout << &i ... prints the address of i, not its value.