Creating ByteArray in Kotlin

Question

Is there a better/shorter way in creating byte array from constant hex than the version below?

byteArrayOf(0xA1.toByte(), 0x2E.toByte(), 0x38.toByte(), 0xD4.toByte(), 0x89.toByte(), 0xC3.toByte())

I tried to put 0xA1 without .toByte() but I receive syntax error complaint saying integer literal does not conform to the expected type Byte. Putting integer is fine but I prefer in hex form since my source is in hex string. Any hints would be greatly appreciated. Thanks!

question from:https://stackoverflow.com/questions/51403881/creating-bytearray-in-kotlin

Answer 1

as an option you can create simple function

fun byteArrayOfInts(vararg ints: Int) = ByteArray(ints.size) { pos -> ints[pos].toByte() }

and use it

val arr = byteArrayOfInts(0xA1, 0x2E, 0x38, 0xD4, 0x89, 0xC3)