javascript - Scrape <script> tag in PHP Goutte

Question

I am scraping a website using PHP Goutte, but I need some informations that are indicated only in a script tag in the following way:

<script>
player.qualityselector({
        sources: [
          { format: 'auto', src: "xxx.example.com", type: 'video/mp4'},
                        { format: '1080p WEB-DL', src: "xxx.example.com", type: 'video/mp4'},
                          { format: '720p WEB-DL', src: "xxx.example.com", type: 'video/mp4'},
                          { format: '480p WEB-DL', src: "xxx.example.com4", type: 'video/mp4'},
                          { format: '360p WEB-DL', src: "xxx.example.com", type: 'video/mp4'},
                          { format: '240p WEB-DL', src: "xxx.example.com", type: 'video/mp4'},
      ],
      });
</script>

I need the src of each one, is that possible?

question from:https://stackoverflow.com/questions/65626028/scrape-script-tag-in-php-goutte

Answer 1

You can use regular expressions.

Example

$page_content = <<<EOF
<script>
player.qualityselector({
        sources: [
          { format: 'auto', src: "xxx.example.com", type: 'video/mp4'},
                        { format: '1080p WEB-DL', src: "xxx.example.com", type: 'video/mp4'},
                          { format: '720p WEB-DL', src: "xxx.example.com", type: 'video/mp4'},
                          { format: '480p WEB-DL', src: "xxx.example.com4", type: 'video/mp4'},
                          { format: '360p WEB-DL', src: "xxx.example.com", type: 'video/mp4'},
                          { format: '240p WEB-DL', src: "xxx.example.com", type: 'video/mp4'},
      ],
      });
</script>
EOF;

preg_match_all('/src:s"(.*)"/', $page_content, $match);
$result = $match[1];
print_r($result);

Output

Array
(
    [0] => xxx.example.com
    [1] => xxx.example.com
    [2] => xxx.example.com
    [3] => xxx.example.com4
    [4] => xxx.example.com
    [5] => xxx.example.com
)