mongoose - MongoDB return all documents (even if they are double)

Question

Let say I have an array with some document _id's:

const ids = ["5ffd5eb822084969b4dc9f74","5ffd5eb822084969b4dc9f74"]

As you can see, there are duplicated, so I want both documents back from Mongo. But with the Document.find({_id: {$in: ids}}) query and the $all option only one document is returned.

Is there a way to get the transaction twice (in this case) back from Mongo?

question from:https://stackoverflow.com/questions/65682160/mongodb-return-all-documents-even-if-they-are-double

Answer 1

You can use a for loop iterate over the array of ids and and use Document.find(id) multiple times.

const ids = ["5ffd5eb822084969b4dc9f74","5ffd5eb822084969b4dc9f74"];
const result = [];
// Loop through each element
ids.forEach(async(id) => {
    const foundResult = await Document.find({_id: id});
    result.push(foundResult);
})

Then you can use the result array.