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c++ - How to change the address of a pointer of a parameter in a function?

I created a function to change the value of *a, but it remains unchanged after the function fun has been executed.

Here's my code.

#include<iostream>
using namespace std;
void fun(int *b){
    int *c = new int;
    *c = 4;
    b = c;
}
int main(){
    int *a = new int;
    *a = 2;
    fun(a);
    cout << *a << endl; // the output is 2 but I want it be 4
    return 0;
}

I want *a be 4 in function fun

question from:https://stackoverflow.com/questions/65622928/how-to-change-the-address-of-a-pointer-of-a-parameter-in-a-function

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1 Answer

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by (71.8m points)

There's two ways, first the C++ way is to have a mutable (non-const) reference:

void fun(int& b) {
   b = 4;
}

// Calling
int x = 0;
fun(x);

Then the classic C way is to use a regular pointer:

void fun(int* b) {
   *b = 4;
}

// Calling
int x = 0;
fun(&x);

The reference approach is better because there's less syntax chaff both in calling the function, and in the function's implementation. There's also no risk you might get nullptr, a reference will be defined.

Note: Your use of new here has unintended consequences, like leaking memory. When you allocate with new you are responsible for releasing that memory.


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