java - what happens to the exception thrown in try block if an expectation is thrown again in finally block?

Question

I am trying to understand what happens to the exception thrown in try block, when an exception occurs again in finally block?

After running code below, I only see exception thrown in finally block. I am trying to understand what happens to the exception in thrown in try block?

        try{
            int i = 10/0;
        }
        finally {
                System.out.println("one");

                int[] a = new int[2];
                a[4] = 0;

                System.out.println("two");
        }

question from:https://stackoverflow.com/questions/65938733/what-happens-to-the-exception-thrown-in-try-block-if-an-expectation-is-thrown-ag

Answer 1

The exception in the try block gets discarded and forgotten, as specified in the language specification:

• If execution of the try block completes abruptly because of a throw of a value V, then there is a choice:

....

• If the run-time type of V is not assignment compatible with a catchable exception class of any catch clause of the try statement, then the finally block is executed. Then there is a choice:

• If the finally block completes normally, then the try statement completes abruptly because of a throw of the value V.

• If the finally block completes abruptly for reason S, then the try statement completes abruptly for reason S (and the throw of value V is discarded and forgotten).