makefile - How to determine quickly which one file is compiled in so many same-name source files？

Question

Thanks in advance.

For some reasons I need to read the glibc code, but I can't determine quickly which one file is compiled in so many same-name source files. In my limited experience with glibc, I can't slove this problem. please help me.

For example, there are many sigaction.c in glibc.

nptl/sigaction.c
sysdeps/unix/sysv/linux/arm/sigaction.c
sysdeps/unix/sysv/linux/x86_64/sigaction.c
sysdeps/unix/sysv/linux/sigaction.c
sysdeps/unix/sysv/linux/arc/sigaction.c
sysdeps/unix/sysv/linux/i386/sigaction.c
sysdeps/unix/sysv/linux/sparc/sparc32/sigaction.c
sysdeps/unix/sysv/linux/sparc/sparc64/sigaction.c
sysdeps/unix/sysv/linux/aarch64/sigaction.c
sysdeps/mach/hurd/sigaction.c
signal/sigaction.c

I can subjectively exclude some files that are not related to my platform (x86), but there are still 4 files left.

nptl/sigaction.c
sysdeps/unix/sysv/linux/x86_64/sigaction.c
sysdeps/mach/hurd/sigaction.c
signal/sigaction.c

Usually I compile glibc with adding printf in every source file to distinguish them. Wanted to know if it's good practice to do that and what would be the best way to do that?

I tried to read the Makefile, but the Makefile of glibc was too complicated for me, and it will take me a long time to fully understand it.

If there is no other method, I can only study the glibc compilation framework (is there any documentation about the glibc compilation framework?).

question from:https://stackoverflow.com/questions/65931846/how-to-determine-quickly-which-one-file-is-compiled-in-so-many-same-name-source

Answer 1

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