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in Technique[技术] by (71.8m points)

join two lists in R offset by a lag of 1


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You can do :

as.list(c(rbind(l1, l2)))

#[[1]]
#[1] "a"

#[[2]]
#[1] "d"

#[[3]]
#[1] "b"

#[[4]]
#[1] "e"

#[[5]]
#[1] "c"

#[[6]]
#[1] "f"

与恶龙缠斗过久,自身亦成为恶龙;凝视深渊过久,深渊将回以凝视…
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