The problem here is that you are trying to await
an array of promises rather than a Promise. This doesn't do what you expect.
When the object passed to await
is not a Promise, await
simply returns the value as-is immediately instead of trying to resolve it. So since you passed await
an array (of Promise objects) here instead of a Promise, the value returned by await is simply that array, which is of type Promise<number>[]
.
What you probably want to do is call Promise.all
on the array returned by map
in order to convert it to a single Promise before await
ing it.
According to the MDN docs for Promise.all
:
The Promise.all(iterable)
method returns a promise that resolves
when all of the promises in the iterable argument have resolved, or
rejects with the reason of the first passed promise that rejects.
So in your case:
var arr = [1, 2, 3, 4, 5];
var results: number[] = await Promise.all(arr.map(async (item): Promise<number> => {
await callAsynchronousOperation(item);
return item + 1;
}));
This will resolve the specific error you are encountering here.
Depending on exactly what it is you're trying to do you may also consider using Promise.allSettled
, Promise.any
, or Promise.race
instead of Promise.all
, though in most situations (almost certainly including this one) Promise.all
will be the one you want.
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