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sockets - When is TCP option SO_LINGER (0) required?

I think I understand the formal meaning of the option. In some legacy code I'm handling now, the option is used. The customer complains about RST as response to FIN from its side on connection close from its side.

I am not sure I can remove it safely, since I don't understand when it should be used.

Can you please give an example of when the option would be required?

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For my suggestion, please read the last section: “When to use SO_LINGER with timeout 0”.

Before we come to that a little lecture about:

  • Normal TCP termination
  • TIME_WAIT
  • FIN, ACK and RST

Normal TCP termination

The normal TCP termination sequence looks like this (simplified):

We have two peers: A and B

  1. A calls close()
    • A sends FIN to B
    • A goes into FIN_WAIT_1 state
  2. B receives FIN
    • B sends ACK to A
    • B goes into CLOSE_WAIT state
  3. A receives ACK
    • A goes into FIN_WAIT_2 state
  4. B calls close()
    • B sends FIN to A
    • B goes into LAST_ACK state
  5. A receives FIN
    • A sends ACK to B
    • A goes into TIME_WAIT state
  6. B receives ACK
    • B goes to CLOSED state – i.e. is removed from the socket tables

TIME_WAIT

So the peer that initiates the termination – i.e. calls close() first – will end up in the TIME_WAIT state.

To understand why the TIME_WAIT state is our friend, please read section 2.7 in "UNIX Network Programming" third edition by Stevens et al (page 43).

However, it can be a problem with lots of sockets in TIME_WAIT state on a server as it could eventually prevent new connections from being accepted.

To work around this problem, I have seen many suggesting to set the SO_LINGER socket option with timeout 0 before calling close(). However, this is a bad solution as it causes the TCP connection to be terminated with an error.

Instead, design your application protocol so the connection termination is always initiated from the client side. If the client always knows when it has read all remaining data it can initiate the termination sequence. As an example, a browser knows from the Content-Length HTTP header when it has read all data and can initiate the close. (I know that in HTTP 1.1 it will keep it open for a while for a possible reuse, and then close it.)

If the server needs to close the connection, design the application protocol so the server asks the client to call close().

When to use SO_LINGER with timeout 0

Again, according to "UNIX Network Programming" third edition page 202-203, setting SO_LINGER with timeout 0 prior to calling close() will cause the normal termination sequence not to be initiated.

Instead, the peer setting this option and calling close() will send a RST (connection reset) which indicates an error condition and this is how it will be perceived at the other end. You will typically see errors like "Connection reset by peer".

Therefore, in the normal situation it is a really bad idea to set SO_LINGER with timeout 0 prior to calling close() – from now on called abortive close – in a server application.

However, certain situation warrants doing so anyway:

  • If the a client of your server application misbehaves (times out, returns invalid data, etc.) an abortive close makes sense to avoid being stuck in CLOSE_WAIT or ending up in the TIME_WAIT state.
  • If you must restart your server application which currently has thousands of client connections you might consider setting this socket option to avoid thousands of server sockets in TIME_WAIT (when calling close() from the server end) as this might prevent the server from getting available ports for new client connections after being restarted.
  • On page 202 in the aforementioned book it specifically says: "There are certain circumstances which warrant using this feature to send an abortive close. One example is an RS-232 terminal server, which might hang forever in CLOSE_WAIT trying to deliver data to a stuck terminal port, but would properly reset the stuck port if it got an RST to discard the pending data."

I would recommend this long article which I believe gives a very good answer to your question.


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