The syntax [e1, e2 .. e3]
is really syntactic sugar for enumFromThenTo e1 e2 e3
, which is a function in the Enum
typeclass.
The Haskell standard defines its semantics as follows:
For the types Int
and Integer
, the enumeration functions have the
following meaning:
- The sequence
enumFrom e1
is the list [e1,e1 + 1,e1 + 2,…]
.
- The sequence
enumFromThen e1 e2
is the list [e1,e1 + i,e1 + 2i,…]
,
where the increment, i
, is e2 ? e1
. The increment may be zero or
negative. If the increment is zero, all the list elements are the
same.
- The sequence
enumFromTo e1 e3
is the list [e1,e1 + 1,e1 + 2,…e3]
.
The list is empty if e1 > e3
.
- The sequence
enumFromThenTo e1 e2 e3
is the list [e1,e1 + i,e1 +
2i,…e3]
, where the increment, i
, is e2 ? e1
. If the increment is
positive or zero, the list terminates when the next element would be
greater than e3
; the list is empty if e1 > e3
. If the increment is
negative, the list terminates when the next element would be less than
e3
; the list is empty if e1 < e3
.
This is pretty much what you'd expect, but the Float
and Double
instances are defined differently:
For Float
and Double
, the semantics of the enumFrom
family is given by the rules for Int
above, except that the list terminates when the elements become greater than e3 + i∕2
for positive increment i
, or when they become less than e3 + i∕2
for negative i
.
I'm not really sure what the justification for this is, so the only answer I can give you is that it is that way because it's defined that way in the standard.
You can work around this by enumerating using integers and converting to Float
afterward.
Prelude> map fromIntegral [1, 3 .. 10] :: [Float]
[1.0,3.0,5.0,7.0,9.0]
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