When an error occurs in a Python script on Unix , an email is sent.
I have been asked to add {Testing Environment} to the subject line of the email if the IP address is 192.168.100.37 which is the testing server. This way we can have one version of a script and a way to tell if the email is coming from messed up data on the testing server.
However, when I google I keep finding this code:
import socket
socket.gethostbyname(socket.gethostname())
However, that's giving me the IP address of 127.0.1.1. When I use ifconfig
I get this
eth0 Link encap:Ethernet HWaddr 00:1c:c4:2c:c8:3e
inet addr:192.168.100.37 Bcast:192.168.100.255 Mask:255.255.255.0
UP BROADCAST RUNNING MULTICAST MTU:1500 Metric:1
RX packets:75760697 errors:0 dropped:411180 overruns:0 frame:0
TX packets:23166399 errors:0 dropped:0 overruns:0 carrier:0
collisions:0 txqueuelen:1000
RX bytes:59525958247 (59.5 GB) TX bytes:10142130096 (10.1 GB)
Interrupt:19 Memory:f0500000-f0520000
lo Link encap:Local Loopback
inet addr:127.0.0.1 Mask:255.0.0.0
UP LOOPBACK RUNNING MTU:16436 Metric:1
RX packets:25573544 errors:0 dropped:0 overruns:0 frame:0
TX packets:25573544 errors:0 dropped:0 overruns:0 carrier:0
collisions:0 txqueuelen:0
RX bytes:44531490070 (44.5 GB) TX bytes:44531490070 (44.5 GB)
Firstly, I don't know where it got 127.0.1.1 from, but either way that's not what I want. When I google I keep coming to the same syntax, Bash scripts or netifaces and I'm trying to use standard libraries.
So how can I get the IP address of eth0 in Python?
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