It's easier to understand if you rewrite that as the completely equivalent
// v───v───v───v───v───v───v───v───v───v───v───v─┬┐
// ││
// v──#1 v─#2 v──#3 v─#4 #5
int const * const Method3(int const * const&) const;
then read it from right to left.
#5 says that the entire function declaration to the left is const
, which implies that this is necessarily a member function rather than a free function.
#4 says that the pointer to the left is const
(may not be changed to point to a different address).
#3 says that the int
to the left is const
(may not be changed to have a different value).
#2 says that the pointer to the left is const
.
#1 says that the int
to the left is const
.
Putting it all together, you can read this as a const
member function named Method3
that takes a reference to a const
pointer to an int const
(or a const int
, if you prefer) and returns a const
pointer to an int const
(const int
).
(N.b. #2 is entirely superfluous.)
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