I. XSLT 1.0 solution:
Here is one way to do this in XSLT 1.0 using only the xxx:node-set()
extension function:
<xsl:stylesheet version="1.0"
xmlns:xsl="http://www.w3.org/1999/XSL/Transform"
xmlns:ext="http://exslt.org/common" exclude-result-prefixes="ext">
<xsl:output omit-xml-declaration="yes" indent="yes"/>
<xsl:template match="mark">
<xsl:variable name="vrtfSplit">
<xsl:apply-templates/>
</xsl:variable>
<xsl:for-each select="ext:node-set($vrtfSplit)/*">
<processedItem>
<xsl:value-of select="10 * ."/>
</processedItem>
</xsl:for-each>
</xsl:template>
<xsl:template match="text()" name="split">
<xsl:param name="pText" select="."/>
<xsl:if test="string-length($pText) >0">
<item>
<xsl:value-of select=
"substring-before(concat($pText, ','), ',')"/>
</item>
<xsl:call-template name="split">
<xsl:with-param name="pText" select=
"substring-after($pText, ',')"/>
</xsl:call-template>
</xsl:if>
</xsl:template>
</xsl:stylesheet>
when this transformation is applied to the following XML document:
<mark>1,2,3,4,5</mark>
The wanted, correct output (each item multiplied by 10) is produced:
<processedItem>10</processedItem>
<processedItem>20</processedItem>
<processedItem>30</processedItem>
<processedItem>40</processedItem>
<processedItem>50</processedItem>
II. XSLT 2.0 solution:
<xsl:stylesheet version="2.0"
xmlns:xsl="http://www.w3.org/1999/XSL/Transform"
xmlns:xs="http://www.w3.org/2001/XMLSchema"
exclude-result-prefixes="xs">
<xsl:output omit-xml-declaration="yes" indent="yes"/>
<xsl:template match="mark">
<xsl:for-each select="tokenize(., ',')">
<processedItem>
<xsl:sequence select="10*xs:integer(.)"/>
</processedItem>
</xsl:for-each>
</xsl:template>
</xsl:stylesheet>
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