Welcome to OStack Knowledge Sharing Community for programmer and developer-Open, Learning and Share
Welcome To Ask or Share your Answers For Others

Categories

0 votes
461 views
in Technique[技术] by (71.8m points)

python - Polar contour plot in matplotlib - best (modern) way to do it?

Update: I've done a full write-up of the way I found to do this on my blog at http://blog.rtwilson.com/producing-polar-contour-plots-with-matplotlib/ - you may want to check there first.

I'm trying to plot a polar contour plot in matplotlib. I've found various resources on the internet, (a) I can't seem to get my code to work and (b) many of the resources appear rather old, and I'm wondering if there is a better way now. For example, http://www.mail-archive.com/[email protected]/msg01953.html suggests that something may be done to improve things soon, and that was in 2006!

I'd love to be able to plot proper polar contour plots - like pcolor lets you do for its type of plot (see commented out section below), but I can't seem to find any way to do that, so I'm converting to cartesian co-ordinates first.

Anyway, I have the code that follows:

from pylab import *
import numpy as np

azimuths = np.arange(0, 360, 10)
zeniths = np.arange(0, 70, 10)
values = []

for azimuth in azimuths:
  for zenith in zeniths:
    print "%i %i" % (azimuth, zenith)
    # Run some sort of model and get some output
    # We'll just use rand for this example
    values.append(rand())

theta = np.radians(azimuths)

values = np.array(values)
values = values.reshape(len(zeniths), len(azimuths))

# This (from http://old.nabble.com/2D-polar-surface-plot-td28896848.html)
# works fine
##############
# Create a polar axes
# ax = subplot(111, projection='polar')
# pcolor plot onto it
# c = ax.pcolor(theta, zeniths, values)
# show()

r, t = np.meshgrid(zeniths, azimuths)

x = r*np.cos(t)
y = r*np.sin(t)

contour(x, y, values)

When I run that I get an error TypeError: Inputs x and y must be 1D or 2D.. I'm not sure why I get this, as both x and y are 2D. Am I doing something wrong?

Also, it seems rather clunky to be putting my values returned from my model into a list and then reshaping it. Is there a better way to do this?

See Question&Answers more detail:os

与恶龙缠斗过久,自身亦成为恶龙;凝视深渊过久,深渊将回以凝视…
Welcome To Ask or Share your Answers For Others

1 Answer

0 votes
by (71.8m points)

You should just be able to use ax.contour or ax.contourf with polar plots just as you normally would... You have a few bugs in your code, though. You convert things to radians, but then use the values in degrees when you plot. Also, you're passing in r, theta to contour when it expects theta, r.

As a quick example:

import numpy as np
import matplotlib.pyplot as plt

#-- Generate Data -----------------------------------------
# Using linspace so that the endpoint of 360 is included...
azimuths = np.radians(np.linspace(0, 360, 20))
zeniths = np.arange(0, 70, 10)

r, theta = np.meshgrid(zeniths, azimuths)
values = np.random.random((azimuths.size, zeniths.size))

#-- Plot... ------------------------------------------------
fig, ax = plt.subplots(subplot_kw=dict(projection='polar'))
ax.contourf(theta, r, values)

plt.show()

enter image description here


与恶龙缠斗过久,自身亦成为恶龙;凝视深渊过久,深渊将回以凝视…
Welcome to OStack Knowledge Sharing Community for programmer and developer-Open, Learning and Share
Click Here to Ask a Question

...