Welcome to OStack Knowledge Sharing Community for programmer and developer-Open, Learning and Share
Welcome To Ask or Share your Answers For Others

Categories

0 votes
385 views
in Technique[技术] by (71.8m points)

.net - Wildcard equivalent in C# generics

Let's say I have a generic class as follows:

public class GeneralPropertyMap<T>
{
}

In some other class I have a method that takes in an array of GeneralPropertyMap<T>. In Java, in order to take in an array that contains any type of GeneralPropertyMap the method would look like this:

private void TakeGeneralPropertyMap(GeneralPropertyMap<?>[] maps)
{
}

We use the wildcard so that later we can call TakeGeneralPropertyMap passing a bunch of GeneralPropertyMap with any type for T each, like this:

GeneralPropertyMap<?>[] maps = new GeneralPropertyMap<?>[3];
maps[0] = new GeneralPropertyMap<String>();
maps[1] = new GeneralPropertyMap<Integer>();
maps[2] = new GeneralPropertyMap<Double>();
//And finally pass the array in.
TakeGeneralPropertyMap(maps);

I'm trying to figure out an equivalent in C# with no success. Any ideas?

See Question&Answers more detail:os

与恶龙缠斗过久,自身亦成为恶龙;凝视深渊过久,深渊将回以凝视…
Welcome To Ask or Share your Answers For Others

1 Answer

0 votes
by (71.8m points)

Generics in C# make stronger guarantees than generics in Java. Therefore, to do what you want in C#, you have to let the GeneralPropertyMap<T> class inherit from a non-generic version of that class (or interface).

public class GeneralPropertyMap<T> : GeneralPropertyMap
{
}

public class GeneralPropertyMap
{
    // Only you can implement it:
    internal GeneralPropertyMap() { }
}

Now you can do:

private void TakeGeneralPropertyMap(GeneralPropertyMap[] maps)
{
}

And:

GeneralPropertyMap[] maps = new GeneralPropertyMap[3];
maps[0] = new GeneralPropertyMap<String>();
maps[1] = new GeneralPropertyMap<Integer>();
maps[2] = new GeneralPropertyMap<Double>();
TakeGeneralPropertyMap(maps);

与恶龙缠斗过久,自身亦成为恶龙;凝视深渊过久,深渊将回以凝视…
Welcome to OStack Knowledge Sharing Community for programmer and developer-Open, Learning and Share
Click Here to Ask a Question

...