c - convert an integer number into an array

Question

I am trying to convert an integer number in C into an array containing each of that number's digits

i.e. if I have

int number = 5400

how can I get to

int numberArray[4]

where

numberArray[0] = 0;
numberArray[1] = 0;
numberArray[2] = 4;
numberArray[3] = 5;

Any suggestions gratefully received.

Answer 1

This would work for numbers >= 0

#include <math.h>

char * convertNumberIntoArray(unsigned int number) {
    int length = (int)floor(log10((float)number)) + 1;
    char * arr = new char[length];
    int i = 0;
    do {
        arr[i] = number % 10;
        number /= 10;
        i++;
    } while (number != 0);
    return arr;
}

EDIT: Just a little bit more C style but more cryptic.

#include <math.h>

char * convertNumberIntoArray(unsigned int number) {
    unsigned int length = (int)(log10((float)number)) + 1;
    char * arr = (char *) malloc(length * sizeof(char)), * curr = arr;
    do {
        *curr++ = number % 10;
        number /= 10;
    } while (number != 0);
    return arr;
}