python - Format ints into string of hex

Question

I need to create a string of hex digits from a list of random integers (0-255). Each hex digit should be represented by two characters: 5 - "05", 16 - "10", etc.

Example:

Input: [0,1,2,3,127,200,255], 
Output: 000102037fc8ff

I've managed to come up with:

#!/usr/bin/env python

def format_me(nums):
    result = ""
    for i in nums:
        if i <= 9:
            result += "0%x" % i
        else:
            result += "%x" % i
    return result


print format_me([0,1,2,3,127,200,255])

However, this looks a bit awkward. Is there a simpler way?

Answer 1

Just for completeness, using the modern .format() syntax:

>>> numbers = [1, 15, 255]
>>> ''.join('{:02X}'.format(a) for a in numbers)
'010FFF'