Welcome to OStack Knowledge Sharing Community for programmer and developer-Open, Learning and Share
Welcome To Ask or Share your Answers For Others

Categories

0 votes
471 views
in Technique[技术] by (71.8m points)

bash - How to store the output of a command in a variable at the same time as printing the output?

Say I want to echo something and capture it in a variable, at the same time I see it in my screen.

echo "hello" | tee tmp_file
var=$(< tmp_file)

So now I could see hello in my terminal as well as saving it into the variable $var.

However, is there any way to do this without having to use a temporary file? tee doesn't seem to be the solution, since it says (from man tee) read from standard input and write to standard output and files, whereas here it is two times standard output.

I am in Bash 4.3, if this matters.

See Question&Answers more detail:os

与恶龙缠斗过久,自身亦成为恶龙;凝视深渊过久,深渊将回以凝视…
Welcome To Ask or Share your Answers For Others

1 Answer

0 votes
by (71.8m points)

Use tee to direct it straight to screen instead of stdout

$ var=$(echo hi | tee /dev/tty)
hi
$ echo $var
hi

与恶龙缠斗过久,自身亦成为恶龙;凝视深渊过久,深渊将回以凝视…
Welcome to OStack Knowledge Sharing Community for programmer and developer-Open, Learning and Share
Click Here to Ask a Question

...