For single path just find the element that doesn't have child nodes:
$('body *:not(:has("*"))');
Or, in your more specific case $('#cell0 *:not(:has("*"))');
For multiple paths - what if there are multiple equally nested nodes? This solution will give you an array of all nodes with highest number of ancestors.
var all = $('body *:not(:has("*"))'), maxDepth=0, deepest = [];
all.each( function(){
var depth = $(this).parents().length||0;
if(depth>maxDepth){
deepest = [this];
maxDepth = depth;
}
else if(depth==maxDepth){
deepest.push(this);
}
});
Again, in your situation you probably want to get to table cells' deepest elements, so you're back to a one-liner:
$('#table0 td *:not(:has("*"))');
- this will return a jQuery object containing all the innermost child nodes of every cell in your table.
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