bash - Percent sign % not working in crontab

Question

I have a cron issue with curl:

curl -w "%{time_total}
" -o /dev/null -s http://myurl.com >> ~/log

works great and add a line in log file with total_time.

But the same line with cron doesn't do anything.

It's not a path problem because curl http://myurl.com >> ~/log works.

Answer 1

% is a special character for crontab. From man 5 crontab:

The "sixth" field (the rest of the line) specifies the command to be run. The entire command portion of the line, up to a newline or a "%" character, will be executed by /bin/sh or by the shell specified in the SHELL variable of the cronfile. A "%" character in the command, unless escaped with a backslash (), will be changed into newline characters, and all data after the first % will be sent to the command as standard input.

So you need to escape the % character:

curl -w "%{time_total}
" -o /dev/null -s http://myurl.com >> ~/log

to

curl -w "\%{time_total}
" -o /dev/null -s http://myurl.com >> ~/log
         ^