Welcome to OStack Knowledge Sharing Community for programmer and developer-Open, Learning and Share
Welcome To Ask or Share your Answers For Others

Categories

0 votes
396 views
in Technique[技术] by (71.8m points)

r - Showing string in formula and not as variable in lm fit

I am not able to resolve the issue that when lm(sformula) is executed, it does not show the string that is assigned to sformula. I have a feeling it is generic way R handles argument of a function and not specific to linear regression.

Below is the illustration of the issue through examples. Example 1, has the undesired output lm(formula = sformula). The example 2 is the output I would like i.e., lm(formula = "y~x").

x <- 1:10
y <- x * runif(10)
sformula <- "y~x"

## Example: 1 
lm(sformula)

## Call:
## lm(formula = sformula)

## Example: 2
lm("y~x")

## Call:
## lm(formula = "y~x")
See Question&Answers more detail:os

与恶龙缠斗过久,自身亦成为恶龙;凝视深渊过久,深渊将回以凝视…
Welcome To Ask or Share your Answers For Others

1 Answer

0 votes
by (71.8m points)

How about eval(call("lm", sformula))?

lm(sformula)
#Call:
#lm(formula = sformula)

eval(call("lm", sformula))
#Call:
#lm(formula = "y~x")

Generally speaking there is a data argument for lm. Let's do:

mydata <- data.frame(y = y, x = x)
eval(call("lm", sformula, quote(mydata)))
#Call:
#lm(formula = "y~x", data = mydata)

The above call() + eval() combination can be replaced by do.call():

do.call("lm", list(formula = sformula))
#Call:
#lm(formula = "y~x")

do.call("lm", list(formula = sformula, data = quote(mydata)))
#Call:
#lm(formula = "y~x", data = mydata)

与恶龙缠斗过久,自身亦成为恶龙;凝视深渊过久,深渊将回以凝视…
Welcome to OStack Knowledge Sharing Community for programmer and developer-Open, Learning and Share
Click Here to Ask a Question

...